Optimal. Leaf size=543 \[ \frac {3 x \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {27 x}{8 \left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{8\ 2^{2/3}}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{8\ 2^{2/3}}+\frac {5 \tanh ^{-1}(x)}{8\ 2^{2/3}}-\frac {15 \tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{8\ 2^{2/3}}-\frac {27 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} E\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{16 x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}}+\frac {9\ 3^{3/4} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} F\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{4 \sqrt {2} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}} \]
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Rubi [A]
time = 0.16, antiderivative size = 543, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 7, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {481, 544, 241,
310, 225, 1893, 402} \begin {gather*} \frac {9\ 3^{3/4} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {\left (1-x^2\right )^{2/3}+\sqrt [3]{1-x^2}+1}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} F\left (\text {ArcSin}\left (\frac {-\sqrt [3]{1-x^2}+\sqrt {3}+1}{-\sqrt [3]{1-x^2}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{4 \sqrt {2} \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} x}-\frac {27 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {\left (1-x^2\right )^{2/3}+\sqrt [3]{1-x^2}+1}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} E\left (\text {ArcSin}\left (\frac {-\sqrt [3]{1-x^2}+\sqrt {3}+1}{-\sqrt [3]{1-x^2}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{16 \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )^2}} x}-\frac {5 \sqrt {3} \text {ArcTan}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{8\ 2^{2/3}}-\frac {5 \sqrt {3} \text {ArcTan}\left (\frac {\sqrt {3}}{x}\right )}{8\ 2^{2/3}}+\frac {3 \left (1-x^2\right )^{2/3} x}{8 \left (x^2+3\right )}-\frac {27 x}{8 \left (-\sqrt [3]{1-x^2}-\sqrt {3}+1\right )}-\frac {15 \tanh ^{-1}\left (\frac {x}{\sqrt [3]{2} \sqrt [3]{1-x^2}+1}\right )}{8\ 2^{2/3}}+\frac {5 \tanh ^{-1}(x)}{8\ 2^{2/3}} \end {gather*}
Antiderivative was successfully verified.
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Rule 225
Rule 241
Rule 310
Rule 402
Rule 481
Rule 544
Rule 1893
Rubi steps
\begin {align*} \int \frac {x^4}{\sqrt [3]{1-x^2} \left (3+x^2\right )^2} \, dx &=\frac {3 x \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {1}{8} \int \frac {3-9 x^2}{\sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx\\ &=\frac {3 x \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}+\frac {9}{8} \int \frac {1}{\sqrt [3]{1-x^2}} \, dx-\frac {15}{4} \int \frac {1}{\sqrt [3]{1-x^2} \left (3+x^2\right )} \, dx\\ &=\frac {3 x \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{8\ 2^{2/3}}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{8\ 2^{2/3}}+\frac {5 \tanh ^{-1}(x)}{8\ 2^{2/3}}-\frac {15 \tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{8\ 2^{2/3}}-\frac {\left (27 \sqrt {-x^2}\right ) \text {Subst}\left (\int \frac {x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{16 x}\\ &=\frac {3 x \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{8\ 2^{2/3}}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{8\ 2^{2/3}}+\frac {5 \tanh ^{-1}(x)}{8\ 2^{2/3}}-\frac {15 \tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{8\ 2^{2/3}}+\frac {\left (27 \sqrt {-x^2}\right ) \text {Subst}\left (\int \frac {1+\sqrt {3}-x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{16 x}-\frac {\left (27 \sqrt {\frac {1}{2} \left (2+\sqrt {3}\right )} \sqrt {-x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{1-x^2}\right )}{8 x}\\ &=\frac {3 x \left (1-x^2\right )^{2/3}}{8 \left (3+x^2\right )}-\frac {27 x}{8 \left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3}}{x}\right )}{8\ 2^{2/3}}-\frac {5 \sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} \left (1-\sqrt [3]{2} \sqrt [3]{1-x^2}\right )}{x}\right )}{8\ 2^{2/3}}+\frac {5 \tanh ^{-1}(x)}{8\ 2^{2/3}}-\frac {15 \tanh ^{-1}\left (\frac {x}{1+\sqrt [3]{2} \sqrt [3]{1-x^2}}\right )}{8\ 2^{2/3}}-\frac {27 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} E\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{16 x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}}+\frac {9\ 3^{3/4} \left (1-\sqrt [3]{1-x^2}\right ) \sqrt {\frac {1+\sqrt [3]{1-x^2}+\left (1-x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}} F\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{1-x^2}}{1-\sqrt {3}-\sqrt [3]{1-x^2}}\right )|-7+4 \sqrt {3}\right )}{4 \sqrt {2} x \sqrt {-\frac {1-\sqrt [3]{1-x^2}}{\left (1-\sqrt {3}-\sqrt [3]{1-x^2}\right )^2}}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 6 vs. order 4 in
optimal.
time = 5.42, size = 157, normalized size = 0.29 \begin {gather*} \frac {1}{8} x \left (x^2 F_1\left (\frac {3}{2};\frac {1}{3},1;\frac {5}{2};x^2,-\frac {x^2}{3}\right )+\frac {3 \left (1-x^2+\frac {9 F_1\left (\frac {1}{2};\frac {1}{3},1;\frac {3}{2};x^2,-\frac {x^2}{3}\right )}{-9 F_1\left (\frac {1}{2};\frac {1}{3},1;\frac {3}{2};x^2,-\frac {x^2}{3}\right )+2 x^2 \left (F_1\left (\frac {3}{2};\frac {1}{3},2;\frac {5}{2};x^2,-\frac {x^2}{3}\right )-F_1\left (\frac {3}{2};\frac {4}{3},1;\frac {5}{2};x^2,-\frac {x^2}{3}\right )\right )}\right )}{\sqrt [3]{1-x^2} \left (3+x^2\right )}\right ) \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {x^{4}}{\left (-x^{2}+1\right )^{\frac {1}{3}} \left (x^{2}+3\right )^{2}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{4}}{\sqrt [3]{- \left (x - 1\right ) \left (x + 1\right )} \left (x^{2} + 3\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^4}{{\left (1-x^2\right )}^{1/3}\,{\left (x^2+3\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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